A friendly conversation with a nub like Raz:
[11:34] ! /q8;\  /q8;\/q8;\Link: Bad Ass Mr. Ass Billy Gunn is the hottest guy in the planet
[11:34] [ZÅ]Raz Admin CanBeBribed: MOFO SHH IM IN A INTENSE BATTLE OF CTF
[11:34] ! /q8;\  /q8;\/q8;\Link: lewl, get gud nubcakes
[12:11] [ZÅ]Raz Admin CanBeBribed: shh i focusing
[12:11] [ZÅ]Raz Admin CanBeBribed: intense game
[12:11] ! /q8;\  /q8;\/q8;\Link: focusing on that flag pole? ;o
[12:11] [ZÅ]Raz Admin CanBeBribed: aye
[12:54] <This user stopped playing Halo>
[12:54] ! /q8;\  /q8;\/q8;\Link: so how did that newbie training pay off?
[12:54] ! /q8;\  /q8;\/q8;\Link: back to Xbox Live and COD Roasts?
[12:55] ! /q8;\  /q8;\/q8;\Link: you are a Brigadier General aren't you?
[12:55] ! /q8;\  /q8;\/q8;\Link: do you want to learn some lessons and advice from a 2 star Major General? you can form a group of 100,000 newbie spartans, but someone like me can give a Brigadier orders into becoming a pro player
[12:56] [ZÅ]Raz Admin CanBeBribed: man
[12:56] [ZÅ]Raz Admin CanBeBribed: that game as bullshit
[12:56] [ZÅ]Raz Admin CanBeBribed: i had retards on my team. other team was full of retards
[12:56] [ZÅ]Raz Admin CanBeBribed: but my team ended up winning in the end
[12:56] [ZÅ]Raz Admin CanBeBribed: god
[12:57] ! /q8;\  /q8;\/q8;\Link: are you sure they weren't Raz clones? D:
[12:57] [ZÅ]Raz Admin CanBeBribed: i dont know when last time i felt this stress lol.
[12:57] [ZÅ]Raz Admin CanBeBribed: thankfully nobody was home
[12:57] [ZÅ]Raz Admin CanBeBribed: i was singing the bible or curse
[12:57] [ZÅ]Raz Admin CanBeBribed: nah they werent raz clones
[12:57] ! /q8;\  /q8;\/q8;\Link: feeling stressed over a newbie pub game is not good, it's just like saying feeling stressed that you can't win over fat and ugly girls like Eva Mendes and Mila Kunis
[12:57] [ZÅ]Raz Admin CanBeBribed: they were doing shit i would never do in 290 million years
[12:57] [ZÅ]Raz Admin CanBeBribed: lol
[12:58] [ZÅ]Raz Admin CanBeBribed: nah im not stress bout them ladies
[12:58] [ZÅ]Raz Admin CanBeBribed: i know the realistic facts
[12:58] [ZÅ]Raz Admin CanBeBribed: they're put in a catargory of....elite.. money..
[12:58] [ZÅ]Raz Admin CanBeBribed: need money
[12:58] [ZÅ]Raz Admin CanBeBribed: so i dont have to worry
[12:58] ! /q8;\  /q8;\/q8;\Link: so Eva Mendes and Mila Kunis wants Raz's wager of $2 an hour from his lawn mowing?
[12:58] [ZÅ]Raz Admin CanBeBribed: since there not a chance in hell im going to be that filthy rich
[12:58] [ZÅ]Raz Admin CanBeBribed: LOL
[12:58] [ZÅ]Raz Admin CanBeBribed: ROFL
[12:58] [ZÅ]Raz Admin CanBeBribed: lmfao
[12:59] [ZÅ]Raz Admin CanBeBribed: niceo ne
[12:59] [ZÅ]Raz Admin CanBeBribed: *bump fist*
[12:59] ! /q8;\  /q8;\/q8;\Link: *fist bump with Raz's wife, if he ever gets one that is*
Vult's pro math skills with ninja:
[11:52] [ZÅ]ninja: ninja too busy doing maths
[11:52] [ZÅ]ninja: \begin{proposition}
$\forall a, b \in \mathbb{N} \; \exists x, y \in \mathbb{Z}$ with $ax + by = (a,
$.
\end{proposition}
\begin{proof}[Proof 1]
Having run Euclid on $a, b$ with output $c = r_n$: have $c$ a linear combination of $r_{n-1}$ and $r_{n-2}$, so $c$ a linear combination of $r_{n-2}$ and $_{n-3}$, ..., and $c$ a linear combination of $r_i$ and $r_{i-1}$ for all $i$ (inductively). Hence $c$ a linear combination of $a$ and $b$.
\end{proof}
\begin{proof}[Proof 2]
Let $h$ be the least positive integer of the form $xa + yb$, some $x, y \in \mathbb{Z}$. Claim: $h = (a,
$.
If $d \mid a$ and $d \mid b$ then $d$ divides every linear combination of $a$ and $b$, hence $d \mid h$.
To show $h \mid a$: suppose not, then write $a = qh + r$, some $q, r \in \mathbb{Z}$ with $1 \leq r \leq h-1$. Then $r = a- qh = a - q(xa + y
$, so $r$ a linear combination of $a$ and $b$, contradicting choice of $h$. So $h \mid a$ and similarly $h \mid b$.
\end{proof}
[12:02] ! /q8;\  /q8;\/q8;\Link: Answer: 1337 because i'm leet like that
[12:03] [ZÅ]ninja:
[12:03] ! /q8;\  /q8;\/q8;\Link: i told you i'm like one of the best mathematicians of the world today
[12:03] ! /q8;\  /q8;\/q8;\Link: because i know math like 1337ness
[12:04] ! /q8;\  /q8;\/q8;\Link: H4RDC0R3 1337
[12:04] [ZÅ]ninja: can you help me with my studies then?
[12:04] ! /q8;\  /q8;\/q8;\Link: sure, i can help you with your math homework anytime
[12:05] [ZÅ]ninja: great
[12:05] ! /q8;\  /q8;\/q8;\Link: if E = MC², then F = MC³, pure genius there
[12:05] [ZÅ]ninja: what's F?
[12:06] [ZÅ]ninja: force?
[12:06] ! /q8;\  /q8;\/q8;\Link: F means the Foot as a distance from a ruler aka either 10 or 14 inches = 1 Foot, that
[12:06] [ZÅ]ninja: Lol
[12:06] [ZÅ]ninja: I'm afraid that your formula is dimensionally inconsistent, Einstein
[12:06] ! /q8;\  /q8;\/q8;\Link: so 28 inches can be put as 2 Feat
[12:07] ! /q8;\  /q8;\/q8;\Link: my formula is like God's Wisdom, unlike Einstein
[12:07] [ZÅ]ninja: Blasphemy
[12:07] ! /q8;\  /q8;\/q8;\Link: no, it's more like Catacalysm
[12:08] ! /q8;\  /q8;\/q8;\Link: speaking of that, i wonder if they made any new World of Warcraft games
[12:08] [ZÅ]ninja: do you really
[12:08] ! /q8;\  /q8;\/q8;\Link: do i really what?
[12:08] [ZÅ]ninja: do you really wonder that
[12:08] ! /q8;\  /q8;\/q8;\Link: yes, because i'm this guy here http://www.blogcdn.com/www.joystiq.com/media/2010/01/wow-nerd-south-park-580.jpg
[12:10] [ZÅ]ninja: I know
[12:39] [ZÅ]ninja: \begin{theorem}[Fermet-Euler Theorem]
For $a$ invertible in $\mathbb{Z}_n$, have $a^{\phi(n)} = 1$ (i.e. if $(a, n) = 1$, then $a^{\phi(n)} \equiv 1 \; (n)$).
\end{theorem}
[12:40] ! /q8;\  /q8;\/q8;\Link: ok
[12:40] ! /q8;\  /q8;\/q8;\Link: let me solve that for you
[12:40] [ZÅ]ninja: are you lost for words by the amazement of the Fermat-Euler theorem?
[12:41] [ZÅ]ninja: oooh, are you going to prove it for me?
[12:41] [ZÅ]ninja: I haven't typed up the proof yet
[12:41] ! /q8;\  /q8;\/q8;\Link: you take all those numbers and letters out, but keep the word math from there because it resembles math
[12:43] [ZÅ]ninja: what?
[12:43] ! /q8;\  /q8;\/q8;\Link: remember the wise words from one of the world's best mathemacians known as [ZÅ]VuLTuR3, notice how i added 3 at the end of my name? to make it look k3wl like math
[12:44] [ZÅ]ninja: oh, this is how I would do it
[12:44] [ZÅ]ninja: Let $x_1, x_2, \ldots x_{\phi(n)}$ be the invertibles in $\mathbb{Z}_n$. Then, in $\mathbb{Z}_n$: $ax_1, ax_2, \ldots, ax_{\phi(n)}$ are distinct (as $a$ is invertible) and invertible (as a product of invertibles). So they are $x_1, \ldots, x_{\phi(n)}$ in some order. Thus $a^{\phi(n)}x_1 x_2 \ldots x_{\phi(n)} = x_1 x_2 \ldots x_{\phi(n)}$, so $a^{\phi(n)} = 1$ (cancelling each $x_i$ in turn).
[12:46] ! /q8;\  /q8;\/q8;\Link: ^ that's like an elementary student trying to solve the square root of 144, which then he made a mistake saying 14 instead of 12, although the real answer to that problem lies within the "x's" because when it comes to math and the letter "x" is involved, it makes math look very sexual
[12:47] [ZÅ]ninja: I haven't a clue what you're on about
[12:49] ! /q8;\  /q8;\/q8;\Link: i have surpassed the knowledge of Einstein, i have a higher education degree on math than him, it is known as mathology. mathology is a mathematical term used when you combine a brain that's gifted with God's Wisdom and mix it into the subject of mathematics
[12:51] [ZÅ]ninja: sounds more like a cult religion
[12:52] ! /q8;\  /q8;\/q8;\Link: it's not when you have God doing all the math for you by giving you some ideas into your brain to solve the problems
: k
